Question 1140321

For the function ​{{{g(x)=(1/3) x-8}}}
​
find {{{g(3)+g(a)}}}

first find  {{{g(3)}}}

{{{g(3)=(1/3) 3-8}}}

{{{g(3)=(1/cross(3)) cross(3)-8}}}

{{{g(3)=1-8}}}

{{{g(3)=-7}}}


now find {{{g(a)}}}

{{{g(a)=(1/3)a-8}}}

and you have


{{{g(3)+g(a)=-7+(1/3)a-8}}}

{{{g(3)+g(a)=(1/3)a-15}}}