Question 1140305
The slope of a line perpendicular to line with slope 5 is -1/5 (negative reciprocal)
point slope formula y-y1=m(x-x1)
y-2=(-1/5)(x-1)
y=(-1/5)x+11/5 (1/5+2)

The slope of AB is 5; parallel lines have the same slope
y-5=5(x+4), note signs
y=5x+25

{{{graph(300,300,-10,10,-10,10,5x-1,(-1/5)x+11/5))}}}