Question 1140308
1 red apple and 3 yellow apples

11C4 are number of ways to select 4=330 possibilities.
7C1*4C3=7*4=28 ways to choose 1 red and 4 yellow
probability is 28/330=0.0848

(7/11)(4/10)(3/9)(2/8)=one way this can happen=168/7920
four ways the red may appear, so total is 672/7920=0.0848