Question 1140248
.
<pre>
The probability to get "2" at the first roll is  {{{2/6}}} = {{{1/3}}}.


The probability to get a "1" at the second roll is  {{{1/6}}}.


The probability to have the requested combination in the requested order is the product


    {{{(1/3)*(1/6)}}} = {{{1/18}}}.    <U>ANSWER</U>
</pre>