Question 1140269
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<pre>
Let x = amount at 8%, in dollars.

Then the amount at 6% is the rest (2000-x) dollars.



The interest from the 8% amount is 0.08*x  dollars.

The interest from the 6%   amount is 0.06*(2000-x)   dollars.



Your equation is


    interest at 8% - 2*(interest at 6%)   = 20  dollars,   or


    0.08*x         - 2*0.06*(2000-x)      = 20  dollars.


Simplify this equation, express x and calculate the answer


    0.08x - 2*0.06*2000 + 0.12x = 20,


    x = {{{(20 + 2*0.06*2000)/(0.08+0.12)}}} = 1300.


<U>Answer</U>.  The amount at 8% is $1300;  the rest  $2000-$1300 = $700 is the amount at 6%.


<U>Check</U>.   0.08*1300 - 2*0.06*700 = 20 dollars.   ! Correct !
</pre>

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It is a typical and standard problem on investment.


To see many other similar solved problems on investment, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.