Question 1140142
Each group of 3 can have {{{ 3*2*1 = 6 }}} ways
to make up the 3 offices, so this is a permutation
problem, not a combination problem
P( 18,3 ) = {{{ 18! / ( 18 -3 )! }}}
P( 18,3 ) = {{{ 18! / 15! }}}
P( 18,3 ) = {{{ 18*17*16 }}}
P( 18,3 ) = {{{ 4896 }}} different ways
get a 2nd opinion if needed