Question 1140018
The mean is 106/10 or 10.6
The sd, of sample is 5.08
90% CI has half-interval of t df=9, 0.975 *5.08/sqrt (10)
t is 1.833
the half-interval is 1.833*5.08/sqrt(10)=2.94
the 90% CI is (7.66, 13.54)
for 95% CI, the t is 2.262 and the half-interval is 3.63 
the 95% CI is (6.97, 14.23)