Question 1140088

a parking lot has a perimeter of {{{P=16000ft}}}.

=>{{{P=2(L+W)}}} where {{{L}}} is length and {{{W}}} width

{{{2(L+W)=16000ft}}}

if the width is {{{40ft}}} more than {{{twice}}} the length, we have

{{{W=2L+40ft}}} 

then

{{{2(L+2L+40ft)=16000ft}}}

{{{L+2L+40ft=16000ft/2}}}

{{{3L+40ft=8000ft}}}

{{{3L=8000ft-40ft}}}

{{{3L=7960ft}}}

{{{L=7960ft/3}}}

{{{L=2653.3ft}}}


{{{W=2L+40ft}}} 

{{{W=2*2653.3ft+40ft}}} 

{{{W=5306.6ft+40ft}}} 

{{{W=5346.6ft}}} 


check:

{{{2(2653.3ft+5346.6ft)=16000ft}}}

{{{2(7999.9ft)=16000ft}}}

{{{15999.8ft=16000ft}}}

{{{16000ft=16000ft}}}