Question 1140035
substitute 40 for y
0.005*1600=8
-0.01*40=-0.4
+119
126.6

for the other it is 131=0.005y^2-0.01y+119
or 0.005y^2-0.01y-12=0
multiply by 200to clear decimals
y^2-2y-2400=0
y=(1/2)(2+ sqrt(4+9600))
=50 years old