Question 1140056
.


Let the three persons be  A,  B  and  C.


Case 1.   The person  A  receives nothing.


<pre>
    Then the person B receives some subset of 5 different objects, and the person C receives the rest 
    (receives the complement to the set that B receives).


    So, there are as many different ways to distribute in this case, as many there are different subsets 
    in the set of 5 elements.


    The answer to the last question is well known: there are {{{2^5}}} = 32 different subsets of the set 
    of 5 distinguishable objects.


    So, the answer to the case 1 is  {{{2^5}}} = 32 ways.
</pre>

Now, &nbsp;cases when the person &nbsp;B&nbsp; or &nbsp;C &nbsp;receives nothing are absolutely symmetric to Case 1.


So, &nbsp;the answer to the problem's question  is  &nbsp;{{{3*2^5}}} = 3*32 = 96.
</pre>

Solved.