Question 1139822
<br>
{{{ln(x+12)-ln(x+2)=ln(3)}}}<br>
By basic rules of logarithms on the left hand side,<br>
{{{ln((x+12)/(x+2))=ln(3)}}}<br>
Then since the logarithms of the two expressions are equal, the expressions are equal.<br>
{{{(x+12)/(x+2) = 3}}}<br>
This becomes a linear equation which you should be able to solve easily.