Question 1139787
<pre>
If $980 grows to $1000, the interest is $1000-$980 = $20

{{{I = p*r*t}}}

Substitute 20 for I, and 6/12 or 1/2 a year for t

{{{20 = 980*r*expr(1/2)}}}

{{{20=489*r}}}

{{{20/489=r}}}

{{{0.0408997955=r}}}

Answer 4.08997955% (round that off as your teacher told you to.

Edwin</pre>