Question 104281
If the line passes through the points (1/3, -1/5), and (-1/3, -1),

The slope,

{{{m=(y-increment)/(x-increment)}}}

{{{m=(-1-(-1/5))/(-1/3-1/3)}}}

{{{m=(-4/5)/(-2/3)}}}

{{{m=6/5}}}

Using the slope-intercept form, {{{y=mx+b}}}

and, the point (1/3, -1/5)-----------x=1/3, and y=-1/5

{{{y=mx+b}}}

{{{-1/5=(6/5)*(1/3)+b}}}

~{{{1/5=2/5+b}}}

~{{{b=-1/5}}}

Then,

{{{y=6x/5-1/5}}}
{{{5y=6x-1}}}
{{{6x-5y-1=0}}}___________The equation of the line!

Graph:

{{{graph(2000,2000,-15,15,-15,15,6x/5-1/5)}}}