Question 1139737
direct variation equation is y = kx.


when y = d and x = t^2, the formula becomes d = k * t^2.


when d = 144 and t = 3, formula becomes 144 = k * 3^2.


solve for k to get k = 144 / 3^2 = 144 / 9.


k is the constant of variation and remains the same for all problems involved with the same equation.


when t = 6, the formula d = k * t^2 becomes d = 144/9 * 6^2 which becomes d = 144/9 * 36 which results in d = 4 * 155 = 576.


the distance in 6 seconds will be 576 feet.