Question 1139721
.
<pre>
Let x be the speed of the car, in miles per hour.

Then the speed by the jet is  (x+375) mph, according to the condition.


The time spent by the car is  {{{300/x}}} hours.


The time spent by the jet is  {{{1360/(x+375)}}} hours.


The difference is 1 hour, which gives you an equation


    {{{300/x}}} - {{{1350/(x+375)}}} = 1.


It is the "time" equation.

To slve it, multiply both sides by x*(x+375). You will get


    300*(x+375) - 1350x = x*(x+375),


Simplify and solve for x


     300x + 300*375 - 1350x = x^2 + 375x

     x^2 + 1425x - 1112500 = 0

     {{{x{1,2]}}} = {{{(-1425 +- sqrt(1425^2 + 4*112500))/2}}} = {{{(-1425 +- 1575)/2}}}.


Of the two roots, only positive root  x = {{{(-1425 + 1575)/2}}} = 75 makes sense.


So, the car's rate is 75 mph;  the jet rate is  (75 + 375) = 450 mph.    <U>ANSWER</U>


<U>CHECK</U>.  {{{300/75}}} - {{{1350/450}}} = 4 - 3 = 1,  exactly in accordance with the condition.
</pre>

Solved.


Using "time" equation is the STANDARD way to solve such problems.


From this solution, &nbsp;learn on how to write, &nbsp;how to use and how to solve a &nbsp;"time" &nbsp;equation.


---------------


To see many other similar solved problems, &nbsp;look into the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Had-a-car-move-faster-it-would-arrive-quicker.lesson>Had a car move faster it would arrive sooner</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/travel/How-far-do-you-live-from-school.lesson>How far do you live from school?</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Earthquake-waves.lesson>Earthquake waves</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Time-equation-HOW-TO-write-it-and-how-to-solve-it.lesson>Time equation: HOW TO use, HOW TO write and HOW TO solve it</A> 

in this site.