Question 1139709
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The product of the roots of the quadratic equation<br>
{{{ax^2+bx+c=0}}}<br>
is {{{c/a}}}.<br>
So in your equation, the product of the roots is {{{k/2}}}.<br>
Since you are given that the product of the roots is 4, k is 8.<br>
Then<br>
{{{2x^2+8x+8 = 0}}}
{{{x^2+4x+4 = 0}}}
{{{(x+2)^2 = 0}}}<br>
The roots are -2 and -2.