Question 104476
{{{-4x^2+13x+12=0}}}

If you multiply both sides by -1,

{{{4x^2-13x-12=0}}}

Since this is the format of a quadratic polynomial, {{{ax^2+bx+c=0}}}, we can apply the quadratic formula.

Also, for this equation a=4, b=-13, c=12

Using the quadratic formula,{{{x =(-b+-sqrt( b^2-4*a*c))/(2*a)}}}

{{{x=(13+-sqrt(13^2-4*4*-12))/(2*4)}}}

{{{x=(13+-sqrt(169+192))/(8)}}}

{{{x=(13+-sqrt(361))/((8))}}}

This means that {{{x=(13+sqrt(361))/((8))}}} or {{{x=(13-sqrt(361))/((8))}}}