Question 1139698
{{{f(x)=5/(x+1) -3}}}...i you are given this, then

the domain will exclude the value of {{{x}}} that makes denominator equal to zero, and it is

{{{(x+1)=0}}}

{{{x=-1}}}

so, domain is:

{ {{{x}}} element {{{R}}}: {{{x<>-1}}} }

interval: ({{{-infinity}}},{{{-1}}}) U ({{{-1}}},{{{infinity}}})

number line:
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range:

if denominator equal to zero, {{{f(x)}}} is undefined => {{{f(x)<>-3}}}

which means, {{{f (x )<-3}}} or {{{f (x )>-3}}}

interval: ({{{-infinity}}},{{{-3}}}) U ({{{-3}}},{{{infinity}}})

so, the range is:

{ {{{f(x)}}} element{{{ R}}} : {{{f(x)<>-3}}} }