Question 1139659
Use compound interest formula with 
yearly compounding:
{{{ A = A[0]*( 1 + r )^t }}}
{{{ A = 22000*( 1 + .03 )^5 }}}
{{{ A  = 22000*1.03^5 }}}
{{{ A = 22000*1.159274 }}}
{{{ A = 25504.03 }}}
The interest plus principal over 5 years is:
$25,504.03
--------------------
The depreciated value of the car after 5 yrs:
{{{ A = A[0]*( 1 - .14 )^5 }}}
{{{ A = 22000*.86^5 }}}
{{{ A = 22000*.47043 }}}
{{{ A = 10349.39 }}}
$10,349.39
----------------------
Over the 5 years, she has spent:
{{{ 25504.03 - 10349.39 = 15154.64 }}}
$15,154.64