Question 1139614
to find the equation of the line passing through ({{{2}}},{{{-1}}}) and ({{{-3}}},{{{8}}}), first use given points to find a slope

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(8-(-1))/(-3-2)}}}

{{{m=(8+1)/-5}}}

{{{m=-9/5}}}

now use point slope formula:

{{{y-y[1]=m(x-x[1])}}}.......plug in {{{m=-9/5}}},({{{2}}},{{{-1}}})

{{{y-(-1)=-(9/5)(x-2)}}}

{{{y+1=-(9/5)x-2(-9/5)}}}

{{{y=-(9/5)x+18/5-1}}}

{{{y=-(9/5)x+18/5-5/5}}}

{{{y=-(9/5)x+13/5}}}=> your equation


{{{drawing( 600, 600, -10, 10, -10, 10,
circle(2,-1,.12),circle(-3,8,.12),locate(2,-1,p(2,-1)),locate(-3,8,p(-3,8)),
 graph( 600, 600, -10, 10, -10, 10, -(9/5)x+13/5)) }}}