Question 1139600
The domain is all real numbers
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The range is y=0, y=1
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This is a discontinuous function, the graph would be just  "dots" at either y = 0 or at y = 1. 
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This is an "even" function, because the negative of any positive rational would have a corresponding y value of 1 and the negative of any positive irrational would have a corresponding y value of 0. Thus, f(x) = f(-x). 
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The y intercept would be the "dot" at (0, 1) - because 0 is rational.
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The "x" intercepts would just be the "dots" where the irrational numbers are located on the number line because "f(x)" would be 0 at those points.
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