Question 1139586
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<pre>
{{{(10-3)^2}}} + {{{(y-(-8))^2}}} = {{{25^2}}}


{{{7^2}}} + {{{(y+8)^2}}} = 625


49 + {{{y+8)^2}}} = 625


{{{(y+8)^2}}} = 625 - 49 = 576


y + 8 = +/- {{{sqrt(576)}}} = +/- 24


y = -8 +/- 24.


{{{y[1]}}} = -8 + 24 = 16;   {{{y[2]}}} = -8 - 24 = -32.


Only positive  {{{y[1]}}} = 16 provides R is located in QI.


<U>ANSWER</U>.  y = 16.
</pre>

Solved.