Question 1139573
Determine whether there is a maximum or minimum value for f(x) = -2x^2 + 3x + 4 and find that value
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The coefficient of the x^2 term is negative --> a maximum
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The max is the vertex of the parabola at x = -b/(2a) = -3/-4 = 3/4
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f(3/4) = -2*(3/4)^2 + 3*(3/4) + 4 = -9/8 + 9/4 + 4 = 41/8