Question 1139478
1.If you throw a ball straight up from a rooftop 160 feet high with an initial speed of 48 feet per​ second, then the formula h=-16t^2+48t+160
describes the​ ball's height h feet above the​ ground, t seconds after you released it. The ball misses the rooftop and eventually strikes the ground.

a) What is the height of the ball one second after you release​ it? 
Solution​:Find 
the value of h in the formula h​=-16t^2+48t+160 when t=1.
Do NOT enter h=_____ feet.  How would we use that?
h(t) = -16t^2+48t+160
It's h(1)
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b) How long will it take the ball to hit the​ ground? 
Solution​:Find the value of t in the formula h=-16t^2+48t+160 when h=0
Yea, do that.
-16t^2 + 48t + 160 = 0
Solve for t.