Question 211
What this really is is a quadratic equation. Note that {{{x^6 = x^3^2}}} (see lesson on logarithms). So, replace {{{x^3}}} with y. You will have: {{{6*y^2+y-15=0}}}. Solve it for y, you can use my quadratic solver on this website which will show work. Once you get y, solve equation {{{x^3 = y}}}, which means take third root of y.