Question 1139495
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Use parentheses where required!  The equation is not P(t) = 1500/ 1 + 8e^(−0.9t)  -->  {{{P(t) = 1500/1+8e^(-0.9t)}}}<br>
The equation is P(t) = 1500/ (1 + 8e^(−0.9t))  -->  {{{P(t) = 1500/(1+8e^(-0.9t))}}}<br>
The carrying capacity is the value of the logistic function for large values of t.<br>
For large values of t, the exponential {{{e^(-0.9t)}}} approaches 0; the value of the function then is<br>
{{{1500/(1+0) = 1500/1 = 1500}}}