Question 1139457
my equation is:


y = 2.5 * sin(144 *x).


my graph is shown below.


<img src = "http://theo.x10hosting.com/2019/042002.jpg" alt="$$$" >


the amplitude id equal to 2.5


that was pretty straight forward.


the frequency used the basic formula of:


frequency = 360 / period.


period = 360 / frequency.


that's when you're dealing in degrees, which i was.


i wanted to find the frequency when the period for one cycle was 2.5 milliseconds.


that's because the picture you had showed two full cycles in 5 milliseconds.


the formula became frequency = 360 / 2.5 which became frequency = 144.


the graph was sized to show 2 full cycles from x = 0 to x = 5.


the center line of the graph was y = 0.


the range of the equation was y = -2.5 to y = 2.5.


the domain of the equation was x = 0 to x = 5.


i shaded the region of the graph that showed x <= - and x >= 5, so that the focus was from x = 0 to x = 5.


y represented the voltage and x represented the milliseconds.


i could be wrong, but i think the frequency of the sound wave was 2 cycles / 5 milliseconds which resulted in .4 cycles per millisecond.


since there are 1000 milliseconds in a second, that would translate to 400 cycles per second.



this would be the normal way to show the frequency of sound waves, but you wanted cycles per millisecond, so i believe your solution is .4 cycles per millisecond.


here's the picture you referenced.


<img src = "https://i.imgur.com/hBff8uL.png" target = "_blank">https://i.imgur.com/hBff8uL.png</a>