<PRE><B>Question 1139379</B>

{{{-2/3 &lt; abs(4d-3) &lt; 2/3 }}}

{{{-2/3 &lt; sqrt((4d-3)^2) &lt; 2/3 }}}

=&gt; first solution: 

{{{-2/3 &lt; 4d-3 &lt; 2/3 }}}

{{{-2/3+3 &lt; 4d-3 +3&lt; 2/3+3 }}}

{{{7/3 &lt; 4d&lt; 11/3 }}}

{{{(7/3)/4 &lt; 4d/4&lt; (11/3)/4 }}}

{{{7/12 &lt; d&lt; 11/12 }}}

=&gt; second solution: 

{{{-2/3 &lt; -(4d-3) &lt; 2/3 }}}

{{{-2/3 &lt; -4d+3&lt; 2/3 }}}

{{{-2/3 -3&lt; -4d+3-3&lt; 2/3-3 }}}

{{{-11/3&lt; -4d&lt; -7/3 }}}

{{{(-11/3)/-4&lt; -4d/-4&lt; (-7/3)/-4 }}}

{{{11/12&gt;d&gt; 7/12 }}}

so,  both are same

{{{7/12&lt;d&lt;11/12}}}


Interval notation: ({{{7/12}}}, {{{11/12}}})

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