Question 1929
lol the first line is perfect, but then you jump in and guess the answer without solving the equation you found. Remember the question says real numbers...not integers, so they might well be decimal numbers.

Also, 0x1 is zero, not 1 so you are definitely wrong :-)

Let x = the smaller of the 2 numbers.

then x(x+1) = 1
so, {{{x^2 + x = 1}}}
and {{{x^2 + x - 1 = 0}}}

putting this into the quadratic formula gives the following answers:

x = {{{(-1 +- sqrt(5))/2}}}

take the positive version, so the 2 numbers are: {{{(-1+sqrt(5))/2}}} and {{{((-1+sqrt(5))/2)+1}}}

jon