Question 104070
Find the axis of symmetry.
	y = x^2 + 5x – 7
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Put in vertex form by completing the square on the x-terms:
x^2+5x+? = y+7+?
x^2+5x+(5/2)^2 = y+7+(5/2)^2
(x+(5/2))^2 = y+(53/4)
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Vertex: (-5/2, -53/4)
Axis: x = -5/2
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{{{graph(400,300,-10,10,-15,10,x^2+5x-7)}}}
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Cheers,
Stan H.