Question 104058
To find the x-intercepts of an equation, you must first solve it as if, y=0,

Then,

{{{y=x^2+5x+2}}}
{{{0=x^2+5x+2}}}

By quadratic formula,

{{{x=(-5+-sqrt(5^2-4*1*2))/(2*1)}}}
{{{x=(5+sqrt(17))/2}}}

or

{{{x=(5-sqrt(17))/2}}}


You're done!!!