Question 1139269
x, amount of the 8% acid
75-x, amount of the 2% acid


Want  75 mL of 5% acid solution --


{{{8x+2(75-x)=5*75}}}

-

{{{8x+2*75-2x=5*75}}}

{{{(8-2)x+2*75=5*75}}}

{{{(8-2)x=(5-2)*75}}}

{{{x=((5-2)*75)/(8-2)}}}

{{{x=(3*75)/6}}}-----------------and do you see that this is HALF the intended volume of the mixture?