Question 1139206
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(a)   The two events are independent.


      It is clear <U>without any science</U> and without any calculations - since after first withdrawing the jelly returns back,

      restoring the situation to its initial stage.



      The second selection experimental step is the same as the first, and has the same basic conditions 

      as the first selection experimental step, and they are totally independent. 



(b)  The probability to get red jelly at the first step is  {{{6/(6+2)}}} = {{{6/8}}} = {{{3/4}}},

      <U>the same</U> as to get red jelly at the second step.


     The probability to get red at the first step <U>and then</U>  to get red at the second step again is the product

         {{{(3/4)*(3/4)}}} =  {{{9/16}}}.
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All questions are answered and the solution is completed.