Question 1139093
{{{log(3,(x+2))+log(3,(x-3))=4}}}
adding logs is multiply
{{{log(3,((x+2)(x-3)))=4}}}
FOIL
{{{log(3,(x^2-x-6))=4}}}
The exponent equiv
x^2-x-6 = {{{3^4}}}
x^2 - x - 6 = 81
x^2 - x - 6 - 81 = 0
x^2 - x - 87 = 0
use the quadratic formula; a=1; b=-1; c=-87
the positive solution only
x = 9.841