Question 1139046
<pre>
first           n
second          n+2
third           n+4
fourth          n+6
</pre>

{{{(n+n+2)^2=2(n+4)(n+6)+516}}}

-

{{{(2n+2)^2=2(n^2+10n+24)+516}}}
{{{2*2(n+1)^2=2(n^2+10n+24)+2*258}}}
{{{2(n^2+2n+1)=(n^2+10n+24)+258}}}
{{{2n^2+4n+2=n^2+10n+282}}}
{{{n^2-6n-280=0}}}
{{{(n+14)(n-20)=0}}}
{{{highlight(n=20)}}}


The integers should be  20, 22,  24,  26.