Question 1139013
.
<pre>

Let x = amount at 16%.

Then the amount at 8% is the rest (50000-x).



The interest from the 16% amount is 0.16*x.

The interest from the 8%   amount is 0.08*(50000-x).



Your equation is


    <U>interest</U> + <U>interest</U>       = <U>total interest</U>,   or


    0.16*x   + 0.08*(50000-x) = 5000.


From the equation, express x and calculate the answer


    x = {{{(5000 - 0.08*50000)/(0.16-0.08)}}} = 12500.


<U>Answer</U>.  The amount at 16% is $12500;  the rest  $50000-$12500 = $37500 is the amount at 8%.


<U>Check</U>.   0.16*12500 + 0.08*37500 = 5000.   ! Correct !
</pre>

-----------------


It is a typical and standard problem on investment.


To see many other similar solved problems on investment, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.