Question 104002


First convert the standard equation {{{x+3y=12}}} into slope intercept form


*[invoke converting_linear_equations "standard_to_slope-intercept", 1, 3, 12, 2, 1]




Now let's find the equation of the line that is perpendicular to {{{y=(-1/3)x+4}}} which goes through (9,-5)


*[invoke equation_parallel_or_perpendicular "perpendicular", "-1/3", "4", 9,-5]


Now convert {{{y=3x-32}}} into standard form



*[invoke converting_linear_equations "slope-intercept_to_standard", 1, 3, 12, 3, -32]



So the equation of the line that is perpendicular to x + 3y = 12 and passing through (9, -5) is



{{{-3x+y=-32}}}