Question 1138973


 a slope-intercept equation for a line:

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept


if line passes through ({{{8}}}, {{{6}}}) and ({{{-6}}},{{{ 6}}}), use them to find a slope first:

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(6-6)/(-6-8)}}}

{{{m=0/(-14)}}}

{{{m=0}}}=> Note: A {{{zero}}} slope is just the slope of a {{{horizontal}}} {{{line}}}! The {{{y}}}-coordinate never changes no matter what the {{{x}}}-coordinate is! It will always be equal to {{{6}}}. 


so, your equation is: {{{y=6}}}


{{{drawing( 600, 600, -10, 10, -10, 10,
circle(-6,6,.12),locate(-6,6,p(-6,6)),
circle(8,6,.12),locate(8,6,p(8,6)),
 graph( 600, 600, -10, 10, -10, 10, 6,6)) }}}