Question 1138868
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The modulus is  {{{sqrt((-1)^2 + (sqrt(3))^2)}}} = {{{sqrt(1 + 3)}}} = {{{sqrt(4)}}} = +2.



The given complex number is in QII  with  {{{tan(alpha)}}} = {{{sqrt(3)/(-1)}}} = {{{-sqrt(3)}}},  

so the argument  is  {{{alpha}}} = {{{2pi/3}}} = 120°.



Therefore,  {{{-1 + i*sqrt(3)}}} = {{{2*cis(2pi/3))}}} = 2*cis(120°).    <U>ANSWER</U>
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