Question 1138824
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P = 1350e^0.5t
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P = 1350e^(0.5t)

{{{P = 1350e^(0.5t)}}}


You want t when P=20000.
{{{ln(P)=ln(1350)+0.5t}}}

{{{0.5t=ln(P)-ln(1350)}}}

{{{highlight_green(t=2(ln(P)-ln(1350)))}}}
You finish.