Question 1138762


{{{h(x) = 2(x-3)}}} -> (x and 3 are small on top) would be an exponent either {{{2^(x-3)}}} or {{{2x^(-3)}}}; looking at your answer choices, you have

{{{h(x) = 2(x-3)}}}
{{{ f(x) = 2x}}}


{{{ graph( 600, 600, -10, 10, -10, 10, 2x, 2(x-3)) }}}


answer: 3. {{{h(x)}}} is shifted right {{{3}}} units