Question 103989





Lets evaluate {{{f(-2)}}}


{{{f(x)=x^2-7x+10}}} Start with the given polynomial



{{{f(-2)=(-2)^2-7(-2)+10}}} Plug in {{{x=-2}}}



{{{f(-2)=(4)-7(-2)+10}}} Evaluate {{{(-2)^2}}} to get 4

 

{{{f(-2)=4+14+10}}} Multiply -7 and  -2  to get 14

  

{{{f(-2)=28}}} Now combine like terms



So when {{{x=-2}}}, {{{f(x)=28}}}



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Lets evaluate {{{f(0)}}}


{{{f(x)=x^2-7x+10}}} Start with the given polynomial



{{{f(0)=(0)^2-7(0)+10}}} Plug in {{{x=0}}}



{{{f(0)=(0)-7(0)+10}}} Evaluate {{{1(0)^2}}} to get 10

 

{{{f(0)=00+10}}} Multiply -7 and  0  to get 0

  

{{{f(0)=10}}} Now combine like terms



So when {{{x=0}}}, {{{f(x)=10}}}




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Lets evaluate {{{f(5)}}}


{{{f(x)=x^2-7x+10}}} Start with the given polynomial



{{{f(5)=(5)^2-7(5)+10}}} Plug in {{{x=5}}}



{{{f(5)=(25)-7(5)+10}}} Evaluate {{{1(5)^2}}} to get 125

 

{{{f(5)=25-35+10}}} Multiply -7 and  5  to get -35

  

{{{f(5)=0}}} Now combine like terms



So when {{{x=5}}}, {{{f(x)=0}}}