Question 1138707
.
<pre>

The probability to get any of 6 faces up is  {{{1/6}}} for each and evry face.


Therefore, the expected winning for one roll is


        {{{(1/6)*(1000 - (1/6)*500 - (1/6)*500 - (1/6)*500 - (1/6)*500 + (1/6)*100)}}} =


      = {{{(1/6)*(1000 - 500 - 500 - 500 - 500 + 1000)}}} = {{{(1/6)*0}}} = 0.    <U>ANSWER</U>
</pre>

Answered, explained, solved and completed.