Question 1138644

{{{lim(x ->2, (x^2+8x-2))}}}..........plug in the value :{{{x= 2}}} 

={{{(2^2+8*2-2)}}} 
={{{4+16-2}}}
={{{18}}}

answer: {{{lim(x ->2, (x^2+8x-2))=18}}}