Question 1138638
the function S(x)=-4.9t^2+4.9t+58.8 gives the height S, in meters of an object launched with velocity of 4.9 meters per second from a height of 58.8 meters. 
A)Hw long will it take the object to hit the ground?
B)find the interval on which the height of the object is greater than 49m.
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S(x)=-4.9t^2+4.9t+58.8 has no x terms on the right side.
Use S(t)=-4.9t^2+4.9t+58.8 with t in seconds.
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A)How long will it take the object to hit the ground?
S(t)=-4.9t^2+4.9t+58.8 = 0 at impact.
Solve for t
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B)find the interval on which the height of the object is greater than 49m.
S(t)=-4.9t^2+4.9t+58.8 = 49
Solve for t, call it T seconds.
0 < t < T