Question 103947
Find the equation and identify the axis of symmetry, create a suitable table for values, and graph. 
y = x^2 - 5x + 3 
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Table:
If x=0,y=3
If x=1, y= -1
If x=2, y = -3
If x=3, y = -3
If x=4, y = -1
etc.
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Put the equation in vertex form by completing the square on the "x"-terms.
x^2-5x+? = y-3+?
x^2-5x+(5/2)^2 = y-3+(5/2)^2
Factor:
(x-(5/2))^2 = y+(13/4)
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This form tells you 
Vertex is at ((5/2),(-13/4))
Axis of symmetry: x = 5/2
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{{{graph(400,300,-10,10,-10,10,x^2-5x+3)}}}
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Cheers,
Stan H.