Question 1138396
The sin is also negative in the 3rd quadrant
Find vertical coordinate
{{{ b^2 = 3^2 - (-2)^2 }}}
{{{ b^2 = 9 - 4 }}}
{{{ b^2 = 5 }}}
{{{ b = -sqrt(5) }}}
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{{{ sin( theta ) = -sqrt(5)/3 }}}