Question 1138398
 Express  {{{sin(485)}}}° in terms of its reference angle. Show work
{{{485}}}° is equal to {{{360+125}}}°; so, you look for {{{125}}}° which is in Q II

note:
A reference angle is an angle whose measure is between {{{0}}}° and{{{ 90}}}° (not including {{{0}}}° or {{{90}}}°)

If {{{theta}}} is your angle, here’s how to find its reference angle.

Quadrant |Reference Angle
 II............ | <{{{180}}}° - {{{theta}}}
 III ...........|< {{{theta}}} - {{{180}}}°
 IV............| < {{{360}}}° - {{{theta}}}


then,  reference angle is: 

{{{sin(485)}}}° = {{{sin(125)}}}° 

 reference angle: {{{180-125=55}}}°

=>{{{ sin(485) = sin(55)}}}