Question 103931
x^2 - 7x - 1= -7
First you must set up the equation in quadratic form. Ax^2+bx+c=0
In order to do that you must first add -7 to the other side to get...
x^2-7x-1+7=0
x^2-7x+6=0
It is now in quadratic form.
x^2=a
-7=b
6=c
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (--7 +- sqrt( -7^2-4*1*6 ))/(2*1) }}}
You plug all of that into the quadratic formula.
Now you start doing your order of operations.
{{{x = (--7 +- sqrt( 49-24 ))/(2) }}}
{{{x = (--7 +- sqrt( 25 ))/(2) }}}
x = (--7 +- 5/(2)
x = (++7 +- 5/(2) 
x = (++7 + 5/(2)-------->12/2=6
x = (++7 - 5/(2)-------->2/2=1
So the solution set is...
x=6 or x=1