Question 1138147
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part 1....<br>
If x is the fraction REMAINING after each hour and the half-life is 10.4 hours, then<br>
{{{x^(10.4) = .5}}}
{{{10.4*log((x)) = log((.5))}}}
{{{log((x)) = log((.5))/10.4 = -.0289452}}}
{{{x = 10^(-.0289452) = .93552373}}}<br>
Then the hourly decay rate is<br>
{{{1-.93552373 = .06447627}}}<br>
Round the answers as directed....<br>
part 2....<br>
You didn't give any information about an artifact....